division thread

[hercthx]

Hey mods, whast happened to it? I cannot find it!

[Pharaoh Atem]

pulled to be cleaned or just burned down.

[hercthx]

cleaned? of what? did I do something wrong, I was trying to do something positive.

[Pharaoh Atem]

not saying you but other members might have attacked others or broke some rules. it happens all the time. it's nothing against you.

only the mods know why it's really gone. i'm only guessing from my 5 years on gw.

[Skydiver]

it wasn't you, it was others.

when we have a thread that's going off the rails and out of control, we pull it out of sight, so we can deal with cleaning stuff up without having members add more 'trouble' to the mix.

if it's redeemable, it'll be back

[Duneknight]

my best comments were in there

[Derocalypse]

it wasn't you, it was others.

when we have a thread that's going off the rails and out of control, we pull it out of sight, so we can deal with cleaning stuff up without having members add more 'trouble' to the mix.

if it's redeemable, it'll be back

It should be back. I hope its back.

[hercthx]

oh I see awesome thanks for your help. I hope it can be salvaged. there were some great responces. GATE ON!

[Sami_]

10 / 2 = 5

[Galileo_Galilee]

The division of two complex numbers can be accomplished by multiplying the numerator and denominator by the complex conjugate of the denominator, for example, with z_1=a+bi and z_2=c+di, z=z_1/z_2 is given by z = (a+bi)/(c+di)


(1)
= ((a+bi)c+di^_)/((c+di)c+di^_)
(2)

(3)
= ((a+bi)(c-di))/((c+di)(c-di))
(4)
= ((ac+bd)+i(bc-ad))/(c^2+d^2),
(5)

where z^_ denotes the complex conjugate. In component notation with (x,y)=x+iy,
((a,b))/((c,d))=((ac+bd)/(c^2+d^2),(bc-ad)/(c^2+d^2)).

http://mathworld.wolfram.com/ComplexDivision.html

[Briangate78]

it wasn't you, it was others.

when we have a thread that's going off the rails and out of control, we pull it out of sight, so we can deal with cleaning stuff up without having members add more 'trouble' to the mix.

if it's redeemable, it'll be back

For the record it was not me. I've been a good doggie.

[jelgate]

The division of two complex numbers can be accomplished by multiplying the numerator and denominator by the complex conjugate of the denominator, for example, with z_1=a+bi and z_2=c+di, z=z_1/z_2 is given by z = (a+bi)/(c+di)


(1)
= ((a+bi)c+di^_)/((c+di)c+di^_)
(2)

(3)
= ((a+bi)(c-di))/((c+di)(c-di))
(4)
= ((ac+bd)+i(bc-ad))/(c^2+d^2),
(5)

where z^_ denotes the complex conjugate. In component notation with (x,y)=x+iy,
((a,b))/((c,d))=((ac+bd)/(c^2+d^2),(bc-ad)/(c^2+d^2)).

http://mathworld.wolfram.com/ComplexDivision.html

The sad part is I understood that