How many can it dial?
The way I figure is that in our universe (seven chevrons) it can dial:
6 (chevrons in an address) x 37 (chevrons that aren't the PoO) which gives us 222 addresses for the MW galaxy.
I've seen it said on these boards that you would take 6 x 6 x 37 which would give you 1332, and that would be true if you were trying to find all possible combinations of chevrons 1-37. But say ABCDEFZ (Z is the PoO) is an address. One can't make this address FEDCBAZ and have another gate be dialed. Because the chevrons are points in space, ABCDEFZ = FEDCBAZ = every possible combination of those letters. Inserting that second six would also mean that you could make the address AACDEFZ, and with chevrons being fixed points in space making another point in space, this isn't possible (pt A, pt B make a line; pt C, pt D make a line; and pt E , pt F make a line that all intersect in one place: the target gate).
So that's 222 gates for our galaxy. Assuming that all the addresses have planets at their locations and a breathable atmosphere (the ancients usually only put gates on planets that have breathable air, or so Carter says in one episode that I can't remember the name to).
Using the same logic for an 8 chevron address, the gate can dial 259 addresses outside the MW galaxy, giving us a total of 481 addresses that can be dialed. Again, this is assuming that there is a gate at the given address.
I'd rather not go into the ninth chevron, seeing as we don't know for sure what it does yet.
Is my math wrong? Critique, por favor. (BTW, I'm not doing this to make myself look good- I just wanted to see what you guys thought)
The way I figure is that in our universe (seven chevrons) it can dial:
6 (chevrons in an address) x 37 (chevrons that aren't the PoO) which gives us 222 addresses for the MW galaxy.
I've seen it said on these boards that you would take 6 x 6 x 37 which would give you 1332, and that would be true if you were trying to find all possible combinations of chevrons 1-37. But say ABCDEFZ (Z is the PoO) is an address. One can't make this address FEDCBAZ and have another gate be dialed. Because the chevrons are points in space, ABCDEFZ = FEDCBAZ = every possible combination of those letters. Inserting that second six would also mean that you could make the address AACDEFZ, and with chevrons being fixed points in space making another point in space, this isn't possible (pt A, pt B make a line; pt C, pt D make a line; and pt E , pt F make a line that all intersect in one place: the target gate).
So that's 222 gates for our galaxy. Assuming that all the addresses have planets at their locations and a breathable atmosphere (the ancients usually only put gates on planets that have breathable air, or so Carter says in one episode that I can't remember the name to).
Using the same logic for an 8 chevron address, the gate can dial 259 addresses outside the MW galaxy, giving us a total of 481 addresses that can be dialed. Again, this is assuming that there is a gate at the given address.
I'd rather not go into the ninth chevron, seeing as we don't know for sure what it does yet.
Is my math wrong? Critique, por favor. (BTW, I'm not doing this to make myself look good- I just wanted to see what you guys thought)
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