Gate Addresses

[6thMonolith]

Also, as long as an 8 or 9 chevron address hasn't been dialed, the PoO will always be the symbol on top of the gate under chevron 7.

[_Owen_]

Ya, that sounds right.

Owen Macri

[SmartEagle]

OK, it's making a lot more sense now, thanks.

I was doing some calculations yesterday. Since there is a unique point of origin for every stargate, it would seem that from other gates all you would have to do would be to dial that point, and your point, to establish a wormhole. However, that would mean having a stargate with thousands or millions of symbols, because there would have to be one for every other world.

If every gate just had a random address assigned to it, 6 symbols from the 38, there would be 1,987,690,320 different addresses possible.

If the gates do use three intersecting lines to find a point in space, there would be only 248,461,290 different addresses. It wouldn't matter the order you entered pairs of points; they would still give you the same line. Many of those lines would be skew lines, though, so not all of those addresses would work. That would still be one huge stargate.

Just thought that was kind of interesting.

[_Owen_]

The gates would work with only 38 symbols plus the point of origin. The possible permutations of the symbols are 38X37X36X35X34X33 seeing as there are 38 symbols and 6 chevrons. Even with three intersecting lines formed by six points, there would be the same amount of permutations.

Owen Macri

[SmartEagle]

With 38 symbols and 6 chevrons, the number of permutations is 38P6, which is also the same as 38x37x36x35x34x33. It equals 1,987,690,320.

If the order of the pairs did not matter, you would use combinations, so it would look like this: (38C2)x(36C2)x(34C2), which equals 248,461,290.

[_Owen_]

Ok, ok, sorry I did not understand what you were trying to say in your original post.

Owen Macri

[SmartEagle]

That's alright. I guess I was a little too vague.

[_Owen_]

I probably just didn't read it very well.

Owen Macri

[6thMonolith]

With 38 symbols and 6 chevrons, the number of permutations is 38P6, which is also the same as 38x37x36x35x34x33. It equals 1,987,690,320.

If the order of the pairs did not matter, you would use combinations, so it would look like this: (38C2)x(36C2)x(34C2), which equals 248,461,290.

Sounds right to me. I'm still wondering why they call it a combination lock, and not a permutation lock, as order does matter with those pesky things.

[_Owen_]

There are lots of people who might not know what permutations are, but technically you aare right.

Owen Macri

[6thMonolith]

And there are probably tons of people that don't know that the order in combinations don't matter. But if everything was named like that, we wouldn't have any double quarter pounders with cheese. Just half pounders. With cheese.

[_Owen_]

lol, double quarter pounders with cheese!

Owen Macri

[StarDreamer]

newbie here.. Just wanted to say this thread has been really interesting to read as this has been the exact question running through my mind recently.. I just couldn't figure out how the gate addresses worked if they were in fact based on constellations, due to shift and different viewpoints. All the theories seem to make sense, some of which I had thought of too (but on simple terms.. no calculations going on in this head at the moment), and its just nice to know I'm not the only one who was concerned about this!

[_Owen_]

Welcome to the Forum StarDreamer! I hope you enjoy it here, if this thread interested you than try reading some of the others in the Science and Tech section, who knows, you might be interested in them too...

Owen Macri

[Seastallion]

newbie here.. Just wanted to say this thread has been really interesting to read as this has been the exact question running through my mind recently.. I just couldn't figure out how the gate addresses worked if they were in fact based on constellations, due to shift and different viewpoints. All the theories seem to make sense, some of which I had thought of too (but on simple terms.. no calculations going on in this head at the moment), and its just nice to know I'm not the only one who was concerned about this!

New blood is always welcome... So... Welcome..! I suppose you could think of Owen as the 'unofficial' curator of the Science and Tech forum. He's posted in nearly (if not completely) every thread, usually has the last word, and always tries to keep the coals alive. I personally, don't have the patience to do that...