Hi I am fairly new here so not sure if this has been discussed before but here it goes. I was browsing the internet and I found an interesting article concerning stargate addresses.
As Dr. Jackson explained in the stargate movie to connect to a planet using a stargate you need a 7 symbol address, the first six symbols act as co-ordinates, creating three intersecting lines, the destination. The stargate uses the seventh symbol as the point of origin allowing one to plot a straight line course to the destination, as shown in the diagram below.
300px-StargateCoordinates_svg.png
With 38 symbols there are (38×37×36×35×34×33) = 1,987,690,320 possible addresses
There are also 720 possible permutations to each address.
However using the above model some of those permutations should sill yield valid addresses. Take for example the address for Abydos:-
Taurus (A)
Serpens Caput (B)
Capricornus (C)
Monoceros (D)
Sagittarius (E)
Orion (F)
.
Just to make absolutely clear I am in no way taking credit for what is said above, I am just making clear what was said on the other post and bringing it to people’s attention on this forum for discussion. The original article is available here
http://stargate.wikia.com/wiki/Talk:Glyph
As Dr. Jackson explained in the stargate movie to connect to a planet using a stargate you need a 7 symbol address, the first six symbols act as co-ordinates, creating three intersecting lines, the destination. The stargate uses the seventh symbol as the point of origin allowing one to plot a straight line course to the destination, as shown in the diagram below.
300px-StargateCoordinates_svg.png
With 38 symbols there are (38×37×36×35×34×33) = 1,987,690,320 possible addresses
There are also 720 possible permutations to each address.
However using the above model some of those permutations should sill yield valid addresses. Take for example the address for Abydos:-
Taurus (A)
Serpens Caput (B)
Capricornus (C)
Monoceros (D)
Sagittarius (E)
Orion (F)
Let's assume first that the address ABCDEF is interpreted by forming 3 pairs of letters, for the sake of argument let's say it's the first two, the middle two, and the last two. So this address has line AB, line CD, and line EF which intersect to locate a destination. Then geometry says that we can reverse the endpoints of a line, AB = BA, etc. So each pair of endpoints can be written in 2 ways, and since we have 3 sets of endpoints, the means that we get 2^3 ways of dialing the same address just by reversing the endpoints. However, since all the matters is that each endpoint is associated with it's proper 'mate' (ie: A and B, etc), we can think of the address as having 3 pairs which then can be arranged in any order so long as the association between symbols remains the same; in other words: AB CD EF == AB EF CD. This increases the ways to dial a given address by a factor of 6. So for the actual computations:
• We start with all the permutations of the 38 non-point-of-origin symbols: 1,987,690,320
• Then we have to divide by 8 to correct for repeats from simply reversing the endpoints.
• Then we have to divide by 6 to correct for simply rearranging the lines within an address.
• This leaves us with 41,410,215 unique addresses to dial
• We start with all the permutations of the 38 non-point-of-origin symbols: 1,987,690,320
• Then we have to divide by 8 to correct for repeats from simply reversing the endpoints.
• Then we have to divide by 6 to correct for simply rearranging the lines within an address.
• This leaves us with 41,410,215 unique addresses to dial
Just to make absolutely clear I am in no way taking credit for what is said above, I am just making clear what was said on the other post and bringing it to people’s attention on this forum for discussion. The original article is available here
http://stargate.wikia.com/wiki/Talk:Glyph
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